Ошибка cannot call member function without object

This program has the user input name/age pairs and then outputs them, using a class.
Here is the code.

#include "std_lib_facilities.h"

class Name_pairs
{
public:
       bool test();
       void read_names();
       void read_ages();
       void print();
private:
        vector<string>names;
        vector<double>ages;
        string name;
        double age;
};

void Name_pairs::read_names()
{
     cout << "Enter name: ";
     cin >> name;
     names.push_back(name);
     cout << endl;
}

void Name_pairs::read_ages()
{
     cout << "Enter corresponding age: ";
     cin >> age;
     ages.push_back(age);
     cout << endl;
}

void Name_pairs::print()
{
     for(int i = 0; i < names.size() && i < ages.size(); ++i)
             cout << names[i] << " , " << ages[i] << endl;
}

bool Name_pairs::test()
{
   int i = 0;
   if(ages[i] == 0 || names[i] == "0") return false;
   else{
        ++i;
        return true;}
}


int main()
{
    cout << "Enter names and ages. Use 0 to cancel.n";
    while(Name_pairs::test())
    {
     Name_pairs::read_names();
     Name_pairs::read_ages();
     }
     Name_pairs::print();
     keep_window_open();
}

However, in int main() when I’m trying to call the functions I get "cannot call 'whatever name is' function without object." I’m guessing this is because it’s looking for something like variable.test or variable.read_names. How should I go about fixing this?

If you want to call them like that, you should declare them static.

just add static keyword at the starting of the function return type..
and then you can access the member function of the class without object:)
for ex:

static void Name_pairs::read_names()
{
   cout << "Enter name: ";
   cin >> name;
   names.push_back(name);
   cout << endl;
}

answered Jun 4, 2019 at 9:57

You are right — you declared a new use defined type (Name_pairs) and you need variable of that type to use it.

The code should go like this:

Name_pairs np;
np.read_names()

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