Ошибка the filename directory name or volume label syntax is incorrect

I’ve installed and setup the latest version of Android Studio (0.3.6, nov 14 release) but upon trying to build my project (a bare-bones hello world project made with the Android Studio new project wizard) I get the following error:

E:BackupsetcTestProj2>gradlew --stacktrace build
:Test2:preBuild UP-TO-DATE
:Test2:preDefaultFlavorDebugBuild UP-TO-DATE
:Test2:prepareDefaultFlavorDebugDependencies
:Test2:compileDefaultFlavorDebugAidl
:Test2:compileDefaultFlavorDebugRenderscript
:Test2:generateDefaultFlavorDebugBuildConfig
:Test2:mergeDefaultFlavorDebugAssets
:Test2:mergeDefaultFlavorDebugResources
:Test2:processDefaultFlavorDebugManifest
:Test2:processDefaultFlavorDebugResources
:Test2:generateDefaultFlavorDebugSources
:Test2:compileDefaultFlavorDebug
:Test2:dexDefaultFlavorDebug
The filename, directory name, or volume label syntax is incorrect.
:Test2:dexDefaultFlavorDebug FAILED

FAILURE: Build failed with an exception.

* What went wrong:
Execution failed for task ':Test2:dexDefaultFlavorDebug'.
> Could not call IncrementalTask.taskAction() on task ':Test2:dexDefaultFlavorDe
bug'

* Try:
Run with --info or --debug option to get more log output.

* Exception is:
org.gradle.api.tasks.TaskExecutionException: Execution failed for task ':Test2:d
exDefaultFlavorDebug'.
        at org.gradle.api.internal.tasks.execution.ExecuteActionsTaskExecuter.ex
ecuteActions(ExecuteActionsTaskExecuter.java:69)
        at org.gradle.api.internal.tasks.execution.ExecuteActionsTaskExecuter.ex
ecute(ExecuteActionsTaskExecuter.java:46)
        at org.gradle.api.internal.tasks.execution.PostExecutionAnalysisTaskExec
uter.execute(PostExecutionAnalysisTaskExecuter.java:35)
        at org.gradle.api.internal.tasks.execution.SkipUpToDateTaskExecuter.exec
ute(SkipUpToDateTaskExecuter.java:64)
        at org.gradle.api.internal.tasks.execution.ValidatingTaskExecuter.execut
e(ValidatingTaskExecuter.java:58)
        at org.gradle.api.internal.tasks.execution.SkipEmptySourceFilesTaskExecu
ter.execute(SkipEmptySourceFilesTaskExecuter.java:42)
        at org.gradle.api.internal.tasks.execution.SkipTaskWithNoActionsExecuter
.execute(SkipTaskWithNoActionsExecuter.java:52)
        at org.gradle.api.internal.tasks.execution.SkipOnlyIfTaskExecuter.execut
e(SkipOnlyIfTaskExecuter.java:53)
        at org.gradle.api.internal.tasks.execution.ExecuteAtMostOnceTaskExecuter
.execute(ExecuteAtMostOnceTaskExecuter.java:43)
        at org.gradle.api.internal.AbstractTask.executeWithoutThrowingTaskFailur
e(AbstractTask.java:283)
        at org.gradle.execution.taskgraph.AbstractTaskPlanExecutor$TaskExecutorW
orker.executeTask(AbstractTaskPlanExecutor.java:79)
        at org.gradle.execution.taskgraph.AbstractTaskPlanExecutor$TaskExecutorW
orker.processTask(AbstractTaskPlanExecutor.java:63)
        at org.gradle.execution.taskgraph.AbstractTaskPlanExecutor$TaskExecutorW
orker.run(AbstractTaskPlanExecutor.java:51)
        at org.gradle.execution.taskgraph.DefaultTaskPlanExecutor$1.run(DefaultT
askPlanExecutor.java:33)
        at org.gradle.internal.Factories$1.create(Factories.java:22)
        at org.gradle.cache.internal.DefaultCacheAccess.longRunningOperation(Def
aultCacheAccess.java:214)
        at org.gradle.cache.internal.DefaultCacheAccess.longRunningOperation(Def
aultCacheAccess.java:276)
        at org.gradle.cache.internal.DefaultPersistentDirectoryStore.longRunning
Operation(DefaultPersistentDirectoryStore.java:142)
        at org.gradle.api.internal.changedetection.state.DefaultTaskArtifactStat
eCacheAccess.longRunningOperation(DefaultTaskArtifactStateCacheAccess.java:78)
        at org.gradle.execution.taskgraph.DefaultTaskPlanExecutor.process(Defaul
tTaskPlanExecutor.java:31)
        at org.gradle.execution.taskgraph.DefaultTaskGraphExecuter.execute(Defau
ltTaskGraphExecuter.java:86)
        at org.gradle.execution.SelectedTaskExecutionAction.execute(SelectedTask
ExecutionAction.java:29)
        at org.gradle.execution.DefaultBuildExecuter.execute(DefaultBuildExecute
r.java:61)
        at org.gradle.execution.DefaultBuildExecuter.access$200(DefaultBuildExec
uter.java:23)
        at org.gradle.execution.DefaultBuildExecuter$2.proceed(DefaultBuildExecu
ter.java:67)
        at org.gradle.execution.DryRunBuildExecutionAction.execute(DryRunBuildEx
ecutionAction.java:32)
        at org.gradle.execution.DefaultBuildExecuter.execute(DefaultBuildExecute
r.java:61)
        at org.gradle.execution.DefaultBuildExecuter.execute(DefaultBuildExecute
r.java:54)
        at org.gradle.initialization.DefaultGradleLauncher.doBuildStages(Default
GradleLauncher.java:166)
        at org.gradle.initialization.DefaultGradleLauncher.doBuild(DefaultGradle
Launcher.java:113)
        at org.gradle.initialization.DefaultGradleLauncher.run(DefaultGradleLaun
cher.java:81)
        at org.gradle.launcher.exec.InProcessBuildActionExecuter$DefaultBuildCon
troller.run(InProcessBuildActionExecuter.java:64)
        at org.gradle.launcher.cli.ExecuteBuildAction.run(ExecuteBuildAction.jav
a:33)
        at org.gradle.launcher.cli.ExecuteBuildAction.run(ExecuteBuildAction.jav
a:24)
        at org.gradle.launcher.exec.InProcessBuildActionExecuter.execute(InProce
ssBuildActionExecuter.java:35)
        at org.gradle.launcher.exec.InProcessBuildActionExecuter.execute(InProce
ssBuildActionExecuter.java:26)
        at org.gradle.launcher.cli.RunBuildAction.run(RunBuildAction.java:50)
        at org.gradle.api.internal.Actions$RunnableActionAdapter.execute(Actions
.java:171)
        at org.gradle.launcher.cli.CommandLineActionFactory$ParseAndBuildAction.
execute(CommandLineActionFactory.java:201)
        at org.gradle.launcher.cli.CommandLineActionFactory$ParseAndBuildAction.
execute(CommandLineActionFactory.java:174)
        at org.gradle.launcher.cli.CommandLineActionFactory$WithLogging.execute(
CommandLineActionFactory.java:170)
        at org.gradle.launcher.cli.CommandLineActionFactory$WithLogging.execute(
CommandLineActionFactory.java:139)
        at org.gradle.launcher.cli.ExceptionReportingAction.execute(ExceptionRep
ortingAction.java:33)
        at org.gradle.launcher.cli.ExceptionReportingAction.execute(ExceptionRep
ortingAction.java:22)
        at org.gradle.launcher.Main.doAction(Main.java:46)
        at org.gradle.launcher.bootstrap.EntryPoint.run(EntryPoint.java:45)
        at org.gradle.launcher.Main.main(Main.java:37)
        at org.gradle.launcher.bootstrap.ProcessBootstrap.runNoExit(ProcessBoots
trap.java:50)
        at org.gradle.launcher.bootstrap.ProcessBootstrap.run(ProcessBootstrap.j
ava:32)
        at org.gradle.launcher.GradleMain.main(GradleMain.java:23)
        at org.gradle.wrapper.BootstrapMainStarter.start(BootstrapMainStarter.ja
va:33)
        at org.gradle.wrapper.WrapperExecutor.execute(WrapperExecutor.java:130)
        at org.gradle.wrapper.GradleWrapperMain.main(GradleWrapperMain.java:48)
Caused by: org.gradle.api.GradleException: Could not call IncrementalTask.taskAc
tion() on task ':Test2:dexDefaultFlavorDebug'
        at org.gradle.util.JavaMethod.invoke(JavaMethod.java:69)
        at org.gradle.api.internal.project.taskfactory.AnnotationProcessingTaskF
actory$StandardTaskAction.doExecute(AnnotationProcessingTaskFactory.java:219)
        at org.gradle.api.internal.project.taskfactory.AnnotationProcessingTaskF
actory$StandardTaskAction.execute(AnnotationProcessingTaskFactory.java:212)
        at org.gradle.api.internal.project.taskfactory.AnnotationProcessingTaskF
actory$StandardTaskAction.execute(AnnotationProcessingTaskFactory.java:201)
        at org.gradle.api.internal.AbstractTask$TaskActionWrapper.execute(Abstra
ctTask.java:527)
        at org.gradle.api.internal.AbstractTask$TaskActionWrapper.execute(Abstra
ctTask.java:510)
        at org.gradle.api.internal.tasks.execution.ExecuteActionsTaskExecuter.ex
ecuteAction(ExecuteActionsTaskExecuter.java:80)
        at org.gradle.api.internal.tasks.execution.ExecuteActionsTaskExecuter.ex
ecuteActions(ExecuteActionsTaskExecuter.java:61)
        ... 52 more
Caused by: com.android.ide.common.internal.LoggedErrorException: Failed to run c
ommand:
        C:Androidandroid-studio2sdkbuild-toolsandroid-4.4dx.bat --dex --ou
tput E:BackupsetcTestProj2Test2buildlibsTest2-defaultFlavor-debug.dex E:
BackupsetcTestProj2Test2buildclassesdefaultFlavordebug E:BackupsetcTes
tProj2Test2builddependency-cachedefaultFlavordebug
Error Code:
        1
Output:
        The filename, directory name, or volume label syntax is incorrect.

        at com.android.ide.common.internal.CommandLineRunner.runCmdLine(CommandL
ineRunner.java:98)
        at com.android.ide.common.internal.CommandLineRunner.runCmdLine(CommandL
ineRunner.java:69)
        at com.android.builder.AndroidBuilder.convertByteCode(AndroidBuilder.jav
a:998)
        at com.android.builder.AndroidBuilder$convertByteCode.call(Unknown Sourc
e)
        at com.android.build.gradle.tasks.Dex.doFullTaskAction(Dex.groovy:55)
        at com.android.build.gradle.internal.tasks.IncrementalTask.taskAction(In
crementalTask.groovy:96)
        at org.gradle.util.JavaMethod.invoke(JavaMethod.java:62)
        ... 59 more


BUILD FAILED

Total time: 5.923 secs

Following that, I get this error:

Gradle: Execution failed for task ':Test2:dexDefaultFlavorDebug'.
> Could not call IncrementalTask.taskAction() on task ':Test2:dexDefaultFlavorDebug'

So, it looks like something is wrong with the «The filename, directory name, or volume label syntax» but what file? What directory?

I’m guessing it might be something about the separator characters, but I’m not sure and my grasp of gradle is quite weak.

(I have set the path variable, JAVA_HOME variable and JDK_HOME variable to point to my JDK 7_45 directory. I’m running Win 7.)

Edit: My Gradle file looks like this

buildscript {
    repositories {
        mavenCentral()
    }
    dependencies {
        classpath 'com.android.tools.build:gradle:0.6.+'
    }
}
apply plugin: 'android'

repositories {
    mavenCentral()
}

android {
    compileSdkVersion 17
    buildToolsVersion "19.0.0"

    defaultConfig {
        minSdkVersion 17
        targetSdkVersion 17
    }
    buildTypes {
        release {
            runProguard true
            proguardFile getDefaultProguardFile('proguard-android-optimize.txt')
        }
    }
    productFlavors {
        defaultFlavor {
            proguardFile 'proguard-rules.txt'
        }
    }
}

dependencies {
}

The filename directory name or volume label syntax is incorrect error is a common issue in Windows that occurs when the system is unable to process the specified file path or folder name.

In this article, the reader will read about all the reasons behind this error and how they can resolve it. Let’s begin!

Why Does the Filename or Volume Label Syntax Is Incorrect Error Occur?

The filename directory name or volume label syntax is incorrect error occurs when Windows is unable to recognize the file path or folder name due to incorrect syntax. This includes reasons such as; use of invalid characters, incorrect spelling, or exceeding the maximum allowed length for file names.

Some other reasons include in the following list.

• Invalid characters in the file or folder name.
• Too long file or folder name.
• Missing or incorrect volume label.
• Incorrect file or folder path.
• Permission issues.

– Invalid Characters in the File or Folder Name

Windows has certain restrictions on the characters that can be used in file and folder names, such as the use of the forward slash (/) or the colon (:) character. If a file or folder name contains any of these invalid characters, the error message will be displayed.

In this example, the file name “file/name.txt” contains the forward-slash (/) character, which is an invalid character in Windows file and folder names. When the program attempts to open the file for writing, it will raise an error because of the invalid file name.

– Too Long File or Folder Name

Windows also has a maximum limit on the length of files and folder names. If the name of a file or folder exceeds this limit, the error message will be displayed.

Let’s take an example below:

In this example, the file name “this.is.a.very.very.very.very.very.very_really_very_very_very_long_file_name.txt” is too long for Windows, which has a maximum limit on the length of the file and folder names.

When the program attempts to open the file for writing, it will raise an error because of the too long file name.

– Incorrect Volume Label or Missing

The name given to a disc drive is called the volume label. If the volume label is missing or incorrect, the error message will be displayed when attempting to access files or folders on that drive. Let’s take an example:

In this example, the file path “D:/file.txt” assumes that the drive letter D: refers to a valid disk drive with the correct volume label. However, if the drive letter D: is not a valid disk drive or the volume label is incorrect, the error message will be displayed when the program attempts to access the file.

This can occur if the drive is not connected, if the volume label has been changed, or if the drive has been assigned a different letter by the operating system.

– Incorrect File or Folder Path

If the path to a file or folder is incorrect, the error message will be displayed when attempting to access the file or folder. This can happen if the file or folder has been moved, renamed, or deleted.

Let’s see an example:

In this example, the file path “C:/incorrect/path/to/file.txt” assumes that the file is located at the specified path on the C: drive. However, if the file does not exist at the specified path or if the path is incorrect, the error message will be displayed when the program attempts to access the file.

This can occur if the file has been moved, renamed, or deleted or if the path is incorrect due to a typo or a mistake in the program.

– Permission Issues

The error notice will appear if the user doesn’t have authorization to access a file or folder. Let’s see an example below:

In this example, the file path “C:/Program Files/file.txt” assumes that the program has sufficient permissions to write to the file located in the C:/Program Files directory. However, if the program is not running with elevated permissions, it will not be able to write to this location and will raise an error message. This can occur because the C:/Program Files directory is protected by the operating system and requires elevated permissions to modify its contents.

– Syntax Errors

Syntax errors are also one of the most prominent reasons behind this filename directory name error. As per our experience, the syntax errors causing this error can range from minor ones like typos or more significant ones like accidentally using the same name for the file and the module. Some common error variations that occur due to this mistake are:

• The filename, directory name, or volume label syntax is incorrect windows 10.
• The filename, directory name, or volume label syntax is incorrect powershell.
• The filename, directory name, or volume label syntax is incorrect in c#.
• The filename, directory name, or volume label syntax is incorrect. Git.

How To Resolve the Filename or Volume Label Syntax Is Incorrect Error?

To resolve the filename directory name or volume label syntax is incorrect error, the programmer should correct the file path or folder name. Ensure that it adheres to the proper syntax guidelines set by Windows, and does not use invalid characters, exceeds the maximum allowed length, and avoids incorrect spelling.



– Check for Typo Mistakes in the File Name and Path

Ensure that in the program, you have typed the correct spelling of the file name and path, including the correct capitalization and extension. Let’s take an example below:

In this example, the os.path.isfile function is used to check if the file specified by filepath exists. If the file exists, the message “File found: C:UsersUserDocumentsexample.txt” is printed. If the file does not exist, the message “File not found: C:UsersUserDocumentsexample.txt” is printed along with a reminder to check for the typo mistakes in the file name and path.

Ensure that there are no extra spaces before or after the file name or path, as this can cause the error.

Given below is an example:

In this example, the strip technique is used to remove the leading and following spaces from the filename string.

The string is divided into a list of words using the split function, and the join method is used to join the list of words back into a string, with a single space between each word. This effectively replaces multiple spaces with a single space. The corrected filename is then printed to the console.

– Check for Invalid Characters

Ensure that the file name or path does not contain any invalid characters such as < > :” / | ? *, as these are not allowed in Windows. Let’s see an example:

In this example, a string invalid_characters is defined, which contains all the invalid characters. The “any” function is used to check if any of the invalid characters are present in the filename string.

If any invalid characters are found, the message “Invalid characters found in the filename: example<>.txt” is printed along with a reminder to remove the invalid characters. If no invalid characters are found, the message “Filename is valid: example.txt” is printed.

– Shorten the File Name or Path

If the file name or path is too long, try to shorten it and see if that resolves the error. Here is a Python example that demonstrates how to shorten the file name or path:

In this example, a maximum length max_length is defined. If the length of the filepath string is greater than max_length, the file path is shortened by slicing it and adding an ellipsis (“…”) to indicate that it has been shortened.

The shortened filepath is then printed to the console. If the length of the filepath string is less than or equal to max_length, the original file path is printed to the console.

– Use the Correct Syntax

Make sure to use the correct syntax when specifying the file name or path. For example, in a command prompt, use quotes around the path if it contains spaces.

By fixing this mistake, the programmer can remove other error variations, such as:

• The filename, directory name, or volume label syntax is incorrect windows 11.
• The filename, directory name, or volume label syntax is incorrect npm.
• The filename, directory name, or volume label syntax is incorrect in command prompt.
• The filename, directory name, or volume label syntax is incorrect jenkins.

– Try Accessing the File or Folder Using the 8.3 Format

Windows has an 8.3 file name format which can sometimes resolve the error. To access the file or folder using this format, you can use the DIR /X command in a command prompt to get the 8.3 names and then use that name to access the file or folder.

– Try Accessing the File or Folder From a Different Location

Sometimes, the error can occur due to a problem with the location from which you’re trying to access the file or folder. Try accessing it from a different location, such as a different folder or drive, and see if that resolves the error.

Conclusion

After reading this guide in detail, the reader will have in-depth knowledge of this error and how they can resolve it by themselves. Below are some of the important points taken from this article.

• The error occurs when Windows is unable to recognize the file path or folder name due to incorrect syntax.
• The error message indicates that the specified file path or folder name does not adhere to the proper syntax guidelines set by Windows.
• Other possible solutions include trying a different file path or folder name, restarting your computer, or checking for disk errors.

We are confident that after going through this guide, you can now resolve this type of error message on your own. Thank you for reading!

When configuring WDS, in the «Remote Installation Folder Location» phase, you may encounter the following error message:

The Filename, Directory Name, Or Volume Label Syntax Is Incorrect.

This error message appears when the hidden
Administrative Shares are removed from the system. For example, in this scenario, if you execute the
net share command, you can not see any entries for Administrative Shares (like: C$, D$ and so forth).